Integrand size = 22, antiderivative size = 1485 \[ \int \frac {1}{(d+e x)^2 \left (a+b x+c x^2\right )^{5/4}} \, dx=-\frac {4 \left (b c d-b^2 e+2 a c e+c (2 c d-b e) x\right )}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right ) (d+e x) \sqrt [4]{a+b x+c x^2}}-\frac {e \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \left (a+b x+c x^2\right )^{3/4}}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )^2 (d+e x)}+\frac {\sqrt {c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{\left (b^2-4 a c\right )^{3/2} \left (c d^2-b d e+a e^2\right )^2 \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )}+\frac {5 \sqrt [4]{-b^2+4 a c} e^{3/2} (2 c d-b e) \sqrt [4]{-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \arctan \left (\frac {\sqrt [4]{-b^2+4 a c} \sqrt {e} \sqrt [4]{1-\frac {(b+2 c x)^2}{b^2-4 a c}}}{\sqrt {2} \sqrt [4]{c} \sqrt [4]{c d^2-b d e+a e^2}}\right )}{4 \sqrt [4]{c} \left (c d^2-b d e+a e^2\right )^{9/4} \sqrt [4]{a+b x+c x^2}}-\frac {5 \sqrt [4]{-b^2+4 a c} e^{3/2} (2 c d-b e) \sqrt [4]{-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \text {arctanh}\left (\frac {\sqrt [4]{-b^2+4 a c} \sqrt {e} \sqrt [4]{1-\frac {(b+2 c x)^2}{b^2-4 a c}}}{\sqrt {2} \sqrt [4]{c} \sqrt [4]{c d^2-b d e+a e^2}}\right )}{4 \sqrt [4]{c} \left (c d^2-b d e+a e^2\right )^{9/4} \sqrt [4]{a+b x+c x^2}}-\frac {\sqrt [4]{c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) E\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{\sqrt {2} \sqrt [4]{b^2-4 a c} \left (c d^2-b d e+a e^2\right )^2 (b+2 c x)}+\frac {\sqrt [4]{c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right ),\frac {1}{2}\right )}{2 \sqrt {2} \sqrt [4]{b^2-4 a c} \left (c d^2-b d e+a e^2\right )^2 (b+2 c x)}-\frac {5 \sqrt {-b^2+4 a c} e (2 c d-b e)^2 \sqrt {\frac {(b+2 c x)^2}{b^2-4 a c}} \sqrt [4]{-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \operatorname {EllipticPi}\left (-\frac {\sqrt {-b^2+4 a c} e}{2 \sqrt {c} \sqrt {c d^2-b d e+a e^2}},\arcsin \left (\sqrt [4]{1-\frac {(b+2 c x)^2}{b^2-4 a c}}\right ),-1\right )}{4 \sqrt {2} \sqrt {c} \left (c d^2-b d e+a e^2\right )^{5/2} (b+2 c x) \sqrt [4]{a+b x+c x^2}}+\frac {5 \sqrt {-b^2+4 a c} e (2 c d-b e)^2 \sqrt {\frac {(b+2 c x)^2}{b^2-4 a c}} \sqrt [4]{-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} \operatorname {EllipticPi}\left (\frac {\sqrt {-b^2+4 a c} e}{2 \sqrt {c} \sqrt {c d^2-b d e+a e^2}},\arcsin \left (\sqrt [4]{1-\frac {(b+2 c x)^2}{b^2-4 a c}}\right ),-1\right )}{4 \sqrt {2} \sqrt {c} \left (c d^2-b d e+a e^2\right )^{5/2} (b+2 c x) \sqrt [4]{a+b x+c x^2}} \]
[Out]
Time = 2.13 (sec) , antiderivative size = 1485, normalized size of antiderivative = 1.00, number of steps used = 21, number of rules used = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.864, Rules used = {754, 848, 857, 637, 311, 226, 1210, 763, 762, 760, 408, 504, 1227, 551, 455, 65, 304, 211, 214} \[ \int \frac {1}{(d+e x)^2 \left (a+b x+c x^2\right )^{5/4}} \, dx=-\frac {5 \sqrt {4 a c-b^2} e \sqrt {\frac {(b+2 c x)^2}{b^2-4 a c}} \sqrt [4]{-\frac {c \left (c x^2+b x+a\right )}{b^2-4 a c}} \operatorname {EllipticPi}\left (-\frac {\sqrt {4 a c-b^2} e}{2 \sqrt {c} \sqrt {c d^2-b e d+a e^2}},\arcsin \left (\sqrt [4]{1-\frac {(b+2 c x)^2}{b^2-4 a c}}\right ),-1\right ) (2 c d-b e)^2}{4 \sqrt {2} \sqrt {c} \left (c d^2-b e d+a e^2\right )^{5/2} (b+2 c x) \sqrt [4]{c x^2+b x+a}}+\frac {5 \sqrt {4 a c-b^2} e \sqrt {\frac {(b+2 c x)^2}{b^2-4 a c}} \sqrt [4]{-\frac {c \left (c x^2+b x+a\right )}{b^2-4 a c}} \operatorname {EllipticPi}\left (\frac {\sqrt {4 a c-b^2} e}{2 \sqrt {c} \sqrt {c d^2-b e d+a e^2}},\arcsin \left (\sqrt [4]{1-\frac {(b+2 c x)^2}{b^2-4 a c}}\right ),-1\right ) (2 c d-b e)^2}{4 \sqrt {2} \sqrt {c} \left (c d^2-b e d+a e^2\right )^{5/2} (b+2 c x) \sqrt [4]{c x^2+b x+a}}+\frac {5 \sqrt [4]{4 a c-b^2} e^{3/2} \sqrt [4]{-\frac {c \left (c x^2+b x+a\right )}{b^2-4 a c}} \arctan \left (\frac {\sqrt [4]{4 a c-b^2} \sqrt {e} \sqrt [4]{1-\frac {(b+2 c x)^2}{b^2-4 a c}}}{\sqrt {2} \sqrt [4]{c} \sqrt [4]{c d^2-b e d+a e^2}}\right ) (2 c d-b e)}{4 \sqrt [4]{c} \left (c d^2-b e d+a e^2\right )^{9/4} \sqrt [4]{c x^2+b x+a}}-\frac {5 \sqrt [4]{4 a c-b^2} e^{3/2} \sqrt [4]{-\frac {c \left (c x^2+b x+a\right )}{b^2-4 a c}} \text {arctanh}\left (\frac {\sqrt [4]{4 a c-b^2} \sqrt {e} \sqrt [4]{1-\frac {(b+2 c x)^2}{b^2-4 a c}}}{\sqrt {2} \sqrt [4]{c} \sqrt [4]{c d^2-b e d+a e^2}}\right ) (2 c d-b e)}{4 \sqrt [4]{c} \left (c d^2-b e d+a e^2\right )^{9/4} \sqrt [4]{c x^2+b x+a}}-\frac {\sqrt [4]{c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (\frac {2 \sqrt {c} \sqrt {c x^2+b x+a}}{\sqrt {b^2-4 a c}}+1\right )^2}} \left (\frac {2 \sqrt {c} \sqrt {c x^2+b x+a}}{\sqrt {b^2-4 a c}}+1\right ) E\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{c x^2+b x+a}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{\sqrt {2} \sqrt [4]{b^2-4 a c} \left (c d^2-b e d+a e^2\right )^2 (b+2 c x)}+\frac {\sqrt [4]{c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (\frac {2 \sqrt {c} \sqrt {c x^2+b x+a}}{\sqrt {b^2-4 a c}}+1\right )^2}} \left (\frac {2 \sqrt {c} \sqrt {c x^2+b x+a}}{\sqrt {b^2-4 a c}}+1\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{c x^2+b x+a}}{\sqrt [4]{b^2-4 a c}}\right ),\frac {1}{2}\right )}{2 \sqrt {2} \sqrt [4]{b^2-4 a c} \left (c d^2-b e d+a e^2\right )^2 (b+2 c x)}-\frac {e \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \left (c x^2+b x+a\right )^{3/4}}{\left (b^2-4 a c\right ) \left (c d^2-b e d+a e^2\right )^2 (d+e x)}-\frac {4 \left (-e b^2+c d b+2 a c e+c (2 c d-b e) x\right )}{\left (b^2-4 a c\right ) \left (c d^2-b e d+a e^2\right ) (d+e x) \sqrt [4]{c x^2+b x+a}}+\frac {\sqrt {c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) (b+2 c x) \sqrt [4]{c x^2+b x+a}}{\left (b^2-4 a c\right )^{3/2} \left (c d^2-b e d+a e^2\right )^2 \left (\frac {2 \sqrt {c} \sqrt {c x^2+b x+a}}{\sqrt {b^2-4 a c}}+1\right )} \]
[In]
[Out]
Rule 65
Rule 211
Rule 214
Rule 226
Rule 304
Rule 311
Rule 408
Rule 455
Rule 504
Rule 551
Rule 637
Rule 754
Rule 760
Rule 762
Rule 763
Rule 848
Rule 857
Rule 1210
Rule 1227
Rubi steps \begin{align*} \text {integral}& = -\frac {4 \left (b c d-b^2 e+2 a c e+c (2 c d-b e) x\right )}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right ) (d+e x) \sqrt [4]{a+b x+c x^2}}-\frac {4 \int \frac {\frac {1}{4} \left (-4 c^2 d^2-5 b^2 e^2+6 c e (b d+2 a e)\right )+\frac {1}{2} c e (2 c d-b e) x}{(d+e x)^2 \sqrt [4]{a+b x+c x^2}} \, dx}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )} \\ & = -\frac {4 \left (b c d-b^2 e+2 a c e+c (2 c d-b e) x\right )}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right ) (d+e x) \sqrt [4]{a+b x+c x^2}}-\frac {e \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \left (a+b x+c x^2\right )^{3/4}}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )^2 (d+e x)}+\frac {4 \int \frac {\frac {1}{16} \left (16 c^3 d^3-5 b^3 e^3+20 b c e^2 (b d+a e)-16 c^2 d e (b d+4 a e)\right )+\frac {1}{8} c e \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) x}{(d+e x) \sqrt [4]{a+b x+c x^2}} \, dx}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )^2} \\ & = -\frac {4 \left (b c d-b^2 e+2 a c e+c (2 c d-b e) x\right )}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right ) (d+e x) \sqrt [4]{a+b x+c x^2}}-\frac {e \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \left (a+b x+c x^2\right )^{3/4}}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )^2 (d+e x)}+\frac {\left (5 e^2 (2 c d-b e)\right ) \int \frac {1}{(d+e x) \sqrt [4]{a+b x+c x^2}} \, dx}{4 \left (c d^2-b d e+a e^2\right )^2}+\frac {\left (c \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right )\right ) \int \frac {1}{\sqrt [4]{a+b x+c x^2}} \, dx}{2 \left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )^2} \\ & = -\frac {4 \left (b c d-b^2 e+2 a c e+c (2 c d-b e) x\right )}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right ) (d+e x) \sqrt [4]{a+b x+c x^2}}-\frac {e \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \left (a+b x+c x^2\right )^{3/4}}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )^2 (d+e x)}+\frac {\left (2 c \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \sqrt {(b+2 c x)^2}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {b^2-4 a c+4 c x^4}} \, dx,x,\sqrt [4]{a+b x+c x^2}\right )}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )^2 (b+2 c x)}+\frac {\left (5 e^2 (2 c d-b e) \sqrt [4]{-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \int \frac {1}{(d+e x) \sqrt [4]{-\frac {a c}{b^2-4 a c}-\frac {b c x}{b^2-4 a c}-\frac {c^2 x^2}{b^2-4 a c}}} \, dx}{4 \left (c d^2-b d e+a e^2\right )^2 \sqrt [4]{a+b x+c x^2}} \\ & = -\frac {4 \left (b c d-b^2 e+2 a c e+c (2 c d-b e) x\right )}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right ) (d+e x) \sqrt [4]{a+b x+c x^2}}-\frac {e \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \left (a+b x+c x^2\right )^{3/4}}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )^2 (d+e x)}+\frac {\left (\sqrt {c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \sqrt {(b+2 c x)^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b^2-4 a c+4 c x^4}} \, dx,x,\sqrt [4]{a+b x+c x^2}\right )}{\sqrt {b^2-4 a c} \left (c d^2-b d e+a e^2\right )^2 (b+2 c x)}-\frac {\left (\sqrt {c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \sqrt {(b+2 c x)^2}\right ) \text {Subst}\left (\int \frac {1-\frac {2 \sqrt {c} x^2}{\sqrt {b^2-4 a c}}}{\sqrt {b^2-4 a c+4 c x^4}} \, dx,x,\sqrt [4]{a+b x+c x^2}\right )}{\sqrt {b^2-4 a c} \left (c d^2-b d e+a e^2\right )^2 (b+2 c x)}+\frac {\left (5 e^2 (2 c d-b e) \sqrt [4]{-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \text {Subst}\left (\int \frac {1}{\left (-\frac {c (2 c d-b e)}{b^2-4 a c}+e x\right ) \sqrt [4]{1-\frac {\left (b^2-4 a c\right ) x^2}{c^2}}} \, dx,x,-\frac {b c}{b^2-4 a c}-\frac {2 c^2 x}{b^2-4 a c}\right )}{2 \sqrt {2} \left (c d^2-b d e+a e^2\right )^2 \sqrt [4]{a+b x+c x^2}} \\ & = -\frac {4 \left (b c d-b^2 e+2 a c e+c (2 c d-b e) x\right )}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right ) (d+e x) \sqrt [4]{a+b x+c x^2}}-\frac {e \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \left (a+b x+c x^2\right )^{3/4}}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )^2 (d+e x)}+\frac {\sqrt {c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{\left (b^2-4 a c\right )^{3/2} \left (c d^2-b d e+a e^2\right )^2 \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )}-\frac {\sqrt [4]{c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) E\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{\sqrt {2} \sqrt [4]{b^2-4 a c} \left (c d^2-b d e+a e^2\right )^2 (b+2 c x)}+\frac {\sqrt [4]{c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{2 \sqrt {2} \sqrt [4]{b^2-4 a c} \left (c d^2-b d e+a e^2\right )^2 (b+2 c x)}-\frac {\left (5 e^3 (2 c d-b e) \sqrt [4]{-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \text {Subst}\left (\int \frac {x}{\sqrt [4]{1-\frac {\left (b^2-4 a c\right ) x^2}{c^2}} \left (\frac {c^2 (2 c d-b e)^2}{\left (b^2-4 a c\right )^2}-e^2 x^2\right )} \, dx,x,-\frac {b c}{b^2-4 a c}-\frac {2 c^2 x}{b^2-4 a c}\right )}{2 \sqrt {2} \left (c d^2-b d e+a e^2\right )^2 \sqrt [4]{a+b x+c x^2}}-\frac {\left (5 c e^2 (2 c d-b e)^2 \sqrt [4]{-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt [4]{1-\frac {\left (b^2-4 a c\right ) x^2}{c^2}} \left (\frac {c^2 (2 c d-b e)^2}{\left (b^2-4 a c\right )^2}-e^2 x^2\right )} \, dx,x,-\frac {b c}{b^2-4 a c}-\frac {2 c^2 x}{b^2-4 a c}\right )}{2 \sqrt {2} \left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )^2 \sqrt [4]{a+b x+c x^2}} \\ & = -\frac {4 \left (b c d-b^2 e+2 a c e+c (2 c d-b e) x\right )}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right ) (d+e x) \sqrt [4]{a+b x+c x^2}}-\frac {e \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \left (a+b x+c x^2\right )^{3/4}}{\left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )^2 (d+e x)}+\frac {\sqrt {c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{\left (b^2-4 a c\right )^{3/2} \left (c d^2-b d e+a e^2\right )^2 \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )}-\frac {\sqrt [4]{c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) E\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{\sqrt {2} \sqrt [4]{b^2-4 a c} \left (c d^2-b d e+a e^2\right )^2 (b+2 c x)}+\frac {\sqrt [4]{c} \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{2 \sqrt {2} \sqrt [4]{b^2-4 a c} \left (c d^2-b d e+a e^2\right )^2 (b+2 c x)}-\frac {\left (5 e^3 (2 c d-b e) \sqrt [4]{-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt [4]{1-\frac {\left (b^2-4 a c\right ) x}{c^2}} \left (\frac {c^2 (2 c d-b e)^2}{\left (b^2-4 a c\right )^2}-e^2 x\right )} \, dx,x,\left (-\frac {b c}{b^2-4 a c}-\frac {2 c^2 x}{b^2-4 a c}\right )^2\right )}{4 \sqrt {2} \left (c d^2-b d e+a e^2\right )^2 \sqrt [4]{a+b x+c x^2}}-\frac {\left (5 c e^2 (2 c d-b e)^2 \sqrt {\frac {\left (b^2-4 a c\right ) \left (-\frac {b c}{b^2-4 a c}-\frac {2 c^2 x}{b^2-4 a c}\right )^2}{c^2}} \sqrt [4]{-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {1-x^4} \left (e^2-\frac {(2 c d-b e)^2}{b^2-4 a c}-e^2 x^4\right )} \, dx,x,\sqrt [4]{1-\frac {\left (b^2-4 a c\right ) \left (-\frac {b c}{b^2-4 a c}-\frac {2 c^2 x}{b^2-4 a c}\right )^2}{c^2}}\right )}{\sqrt {2} \left (b^2-4 a c\right ) \left (c d^2-b d e+a e^2\right )^2 \left (-\frac {b c}{b^2-4 a c}-\frac {2 c^2 x}{b^2-4 a c}\right ) \sqrt [4]{a+b x+c x^2}} \\ & = \text {Too large to display} \\ \end{align*}
Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.
Time = 12.10 (sec) , antiderivative size = 187, normalized size of antiderivative = 0.13 \[ \int \frac {1}{(d+e x)^2 \left (a+b x+c x^2\right )^{5/4}} \, dx=-\frac {\left (\frac {e \left (b-\sqrt {b^2-4 a c}+2 c x\right )}{c (d+e x)}\right )^{5/4} \left (\frac {e \left (b+\sqrt {b^2-4 a c}+2 c x\right )}{c (d+e x)}\right )^{5/4} \operatorname {AppellF1}\left (\frac {7}{2},\frac {5}{4},\frac {5}{4},\frac {9}{2},\frac {2 c d-\left (b+\sqrt {b^2-4 a c}\right ) e}{2 c (d+e x)},\frac {2 c d-b e+\sqrt {b^2-4 a c} e}{2 c d+2 c e x}\right )}{14 \sqrt {2} e (d+e x) (a+x (b+c x))^{5/4}} \]
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\[\int \frac {1}{\left (e x +d \right )^{2} \left (c \,x^{2}+b x +a \right )^{\frac {5}{4}}}d x\]
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Timed out. \[ \int \frac {1}{(d+e x)^2 \left (a+b x+c x^2\right )^{5/4}} \, dx=\text {Timed out} \]
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\[ \int \frac {1}{(d+e x)^2 \left (a+b x+c x^2\right )^{5/4}} \, dx=\int \frac {1}{\left (d + e x\right )^{2} \left (a + b x + c x^{2}\right )^{\frac {5}{4}}}\, dx \]
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\[ \int \frac {1}{(d+e x)^2 \left (a+b x+c x^2\right )^{5/4}} \, dx=\int { \frac {1}{{\left (c x^{2} + b x + a\right )}^{\frac {5}{4}} {\left (e x + d\right )}^{2}} \,d x } \]
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\[ \int \frac {1}{(d+e x)^2 \left (a+b x+c x^2\right )^{5/4}} \, dx=\int { \frac {1}{{\left (c x^{2} + b x + a\right )}^{\frac {5}{4}} {\left (e x + d\right )}^{2}} \,d x } \]
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Timed out. \[ \int \frac {1}{(d+e x)^2 \left (a+b x+c x^2\right )^{5/4}} \, dx=\int \frac {1}{{\left (d+e\,x\right )}^2\,{\left (c\,x^2+b\,x+a\right )}^{5/4}} \,d x \]
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